题解
【基础】连续非素数的最长度
1 条题解
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#include <iostream> #include <vector> using namespace std; int main() { int n; cin >> n; vector<bool> is_prime(n + 1, true); is_prime[0] = is_prime[1] = false; // 埃氏筛法筛素数 for (int i = 2; i * i <= n; ++i) { if (is_prime[i]) { for (int j = i * i; j <= n; j += i) { is_prime[j] = false; } } } int max_len = 0; int current_len = 0; for (int i = 1; i <= n; ++i) { if (!is_prime[i]) { current_len++; max_len = max(max_len, current_len); } else { current_len = 0; } } cout << max_len << endl; return 0; }
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