题解
【基础】小X数字母
1 条题解
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#include <iostream> #include <string> using namespace std; int main() { int N; string s; cin >> N >> s; int max_count = 0; int current_count = 0; for (char c : s) { if (c == 'A') { current_count++; if (current_count > max_count) { max_count = current_count; } } else { current_count = 0; } } cout << max_count << endl; return 0; }
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