题解
求一元二次方程
1 条题解
-
0
#include<iostream> #include<cmath> #include<iomanip> using namespace std; int main() { double a,b,c,d,x1,x2; cin>>a>>b>>c; d=b*b-4*a*c; if(d>0.000001){ x1=(-b+sqrt(d))/(2*a); x2=(-b-sqrt(d))/(2*a); if(a<0){ cout<<"x1=";printf("%0.5lf",x1);cout<<";"<<"x2=";printf("%0.5lf",x2);} else{ cout<<"x1=";printf("%0.5lf",x2);cout<<";"<<"x2=";printf("%0.5lf",x1); } } if(d >= -0.000001 && d <= 0.000001){ x1=x2=(-b)/(2*a); cout<<"x1=x2=";printf("%0.5lf",x1); } if(d < -0.000001){ cout<<"No answer!"; } return 0; }
- 1