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判断能否被3,5,7整除

1 条题解

  • 0
    @ 2026-7-28 22:45:09
    #include<iostream> 
    using namespace std;
    int main(){
    	int a;
    	cin>>a;
    	if(a%3==0&&a%5==0&&a%7==0){
    		cout<<"3 5 7";
    	} 
    	else if(a%3==0&&a%5==0){
    		cout<<"5 3";
    	}
    	else if(a%3==0&&a%7==0){
    		cout<<"7 3";
    	}
    	else if(a%5==0&&a%7==0){
    		cout<<"7 5";
    	}
    	else if(a%3==0){
    		cout<<"3";
    	}
    	else if(a%5==0){
    		cout<<"5";
    	}
    	else if(a%7==0){
    		cout<<"7";
    	}
    	else
    	cout<<"n";
    	return 0;
    }
    
    • 1