#include <iostream>
using namespace std;

// 计算 n 的所有约数（不包括 n 本身）之和
int getDivisorSum(int n) {
    int sum = 0;
    for (int i = 1; i < n; ++i) {
        if (n % i == 0) {
            sum += i;
        }
    }
    return sum;
}

int main() {
    int a, b;
    cin >> a >> b;

    int sum_a = getDivisorSum(a);
    int sum_b = getDivisorSum(b);

    if (sum_a == b && sum_b == a) {
        cout << "yes" << endl;
    } else {
        cout << "no" << endl;
    }

    return 0;
}